Example 7.1 Section
The astragalus (ankle or heel bone) of animals were used in ancient times as a forerunner of modern dice. In fact, Egyptian tomb paintings show that sheep astragali were used in board games as early as 3500 B.C. (see Figure 7.2). When a sheep astragalus is thrown into the air it can land on one of four sides, which were associated with the numbers 1, 3, 4, and 6 (see Table 7.1). Two sides (the 3 and the 4) are wider and each come up about 40% of the time, while the narrower sides (the 1 and the 6) each come up about 10% of the time. Astragali were used for gambling, games, and divination purposes by the ancients.
Number  % of time it occurs 

1  10% 
3  40% 
4  40% 
6  10% 
Toss an astragalus once. What's the chance you get a "1"?
Solution
The probability of rolling a "1" is 10%. This corresponds to the percentage of time you would get a "1" in a very long sequence of rolls. Here, we can imagine repeating the process of rolling the astragalus many times and with many rolls, the margin of error shrinks and we hone in on an expected relative frequency of times that the event we are looking for happens (getting a "1"). This illustrates the relative frequency interpretation of probability. If a chance process can be repeated independently over and over, the probability of a particular event of interest is just the longrun proportion of times that it happens.Since probabilities can often be viewed as the proportion of times something happens we see our first rule of probability.
Toss an astragalus once. What's the chance you get at least a 3?
Solution
Getting "at least a 3" corresponds to getting either a 3, a 4, or a 6. These occur 40% +40%+10% = 90% of the time so the probability is 0.9. "Getting a 3" and "getting a 4" and "getting a 6" are mutually exclusive events because you can only have one of them happen at the same time (i.e. knowing one thing happened means the other could not have occurred). Our calculation of the probability of "at least a 3" illustrates our second rule of probability.Notice that there is another way to solve the previous problem. The opposite of "at least 3" is "getting a 1" (i.e. the only other possibility) so you can also figure the answer as 100%  10% = 90% or 0.90. This rule of the opposites is our third rule of probability.
Suppose you toss an astralgus twice. What's the chance that you get "4s" on both tosses?
Solution
The probability that you get a 4 on the first toss is 40%. Now, when we toss the second time, the chance is still 40% that you would get a "4". Thus, getting two 4s in a row would occur 40% of 40% = 16% of the time. The calculation is just 0.40x0.40 = 0.16. Notice the assumption built into this calculation. We assume (quite reasonably in this case) that the chances don't change when we are making our second toss, regardless of how the first toss comes out.In ancient Rome, the lowest score in tossing four astragali (getting all four 1s) was called the dog throw. What is the probability of getting a dog throw?
Solution
Since each throw will be independent the probability would be 0.1 × 0.1 × 0.1 × 0.1 = 0.0001 or one chance in 10,000.Example 7.2 Independent or not? Section

For the next two single births at Hershey Medical Center: whether the first baby is a boy and whether the second baby is a boy.
Independent. Whether the first baby is a boy doesn't affect the chances on the next birth (since they are two different mothers 
For the next two single births at Hershey Medical Center: whether the first baby is a girl and whether both babies are girls.
Not Independent. If the first baby is a girl then the chances go up for both babies being girls (in fact, if the first baby is a boy then the chances drop to zero for both being girls). 
For the end of the month in February next year: whether there will be snow on the ground at the State College airport on February 27th and whether there will be snow on the ground at the airport on February 28th
Not independent. Knowing that there will be snow on the ground on the 27th makes the chances go up for there to be snow on February 28th.
Example 7.3 Section
The highest paid employee has randomly selected from the list of Fortune 500 companies. Which of these probabilities is the largest?
 The chance this person is a college graduate
 The chance this person is a college graduate with a Business degree.
 The chance this person is a college graduate with an Engineering degree.
While we can often think of how the process leading to data might be repeated, some events arise in situations that are not easily seen as being repeatable. In such situations, the relative frequency interpretation of probability may seem inappropriate. For example, answering a question like "What is the chance that our next President will be a woman?" would seem to require a different interpretation of the meaning of probability. Luckily, it is perfectly reasonable to assign probabilities to events outside of the relative frequency interpretation as long as they satisfy the above rules of probability. Personal probabilities that satisfy these rules give a coherent interpretation even if they might differ from one person's assignment to another's.