Think About It! Section
Select the answer you think is correct  then click the right arrow to proceed to the next question.
A die is rolled 6 times. Which of the following is the most likely sequence of rolls?

All possibilities are equally likely on each roll so no number is more likely than another regardless of how previous rolls turn out.

All possibilities are equally likely on each roll so no number is more likely than another regardless of how previous rolls turn out.

All possibilities are equally likely on each roll so no number is more likely than another regardless of how previous rolls turn out.

Correct. All possibilities are equally likely on each roll so no number is more likely than another regardless of how previous rolls turn out.
Which of these will follow the normal curve most closely?

The answer is: A histogram of all of the possible sample means from samples of 100 household incomes in Pennsylvania. The population histogram (situation A) is likely to be very skewed to the right and the histogram of the sample data (situation B) is likely to reflect that. The sampling distribution of the mean will look very much like the normal curve – especially for a larger sample (situation C).

The answer is: A histogram of all of the possible sample means from samples of 100 household incomes in Pennsylvania. The population histogram (situation A) is likely to be very skewed to the right and the histogram of the sample data (situation B) is likely to reflect that. The sampling distribution of the mean will look very much like the normal curve – especially for a larger sample (situation C).

Correct. The population histogram (situation A) is likely to be very skewed to the right and the histogram of the sample data (situation B) is likely to reflect that. The sampling distribution of the mean will look very much like the normal curve – especially for a larger sample (situation C).

The answer is: A histogram of all of the possible sample means from samples of 100 household incomes in Pennsylvania. The population histogram (situation A) is likely to be very skewed to the right and the histogram of the sample data (situation B) is likely to reflect that. The sampling distribution of the mean will look very much like the normal curve – especially for a larger sample (situation C).
A company matches employee contributions to a retirement fund up to $10,000 per year. A histogram of the cost for each employee is left skewed (since most employees get close to the maximum but a few do not take advantage of the program). Despite this fact,

Correct. The sampling distribution for a sample of size 50 should be very well approximated by a normal distribution.

The answer is: The distribution of the average cost for a randomly selected group of 50 employees would still follow the normal curve. The sampling distribution for a sample of size 50 should be very well approximated by a normal distribution.

The answer is: The distribution of the average cost for a randomly selected group of 50 employees would still follow the normal curve. The sampling distribution for a sample of size 50 should be very well approximated by a normal distribution.
The average amount spent by customers that attend a New Years Eve party at a restaurant and bar is $83 with a standard deviation of $60. You would expect that a sample of 25 of these customers would spend an average of $83 with a standard deviation of?

The answer is: \($12\). The standard deviation for the sample mean will be the population standard deviation divided by the square root of the sample size = \($60 / 5 = $12\).

Correct. The standard deviation for the sample mean will be the population standard deviation divided by the square root of the sample size = \($60 / 5 = $12\).

The answer is: \($12\). The standard deviation for the sample mean will be the population standard deviation divided by the square root of the sample size = \($60 / 5 = $12\).

The answer is: \($12\). The standard deviation for the sample mean will be the population standard deviation divided by the square root of the sample size = \($60 / 5 = $12\).

The correct answer is \(\sqrt{0.8(0.2)/100} = 0.04\).

The correct answer is \(\sqrt{0.8(0.2)/100} = 0.04\).

Correct. \(\sqrt{0.8(0.2)/100} = 0.04\).

The correct answer is \(\sqrt{0.8(0.2)/100} = 0.04\).