Research question: Is the proportion of NFL overtime coin tosses that are won different from 0.50?
StatKey was used to construct a randomization distribution:
Step 1: Check assumptions and write hypotheses
From the given StatKey output, the sampling distribution is approximately normal.
\(H_a\colon p \ne 0.50\)
Step 2: Calculate the test statistic
The sample statistic is the proportion in the original sample, 0.561. The null parameter is 0.50. And, the standard error is 0.024.
Step 3: Determine the p value
The p value will be the area on the z distribution that is more extreme than the test statistic of 2.542, in the direction of the alternative hypothesis. This is a two-tailed test:
The p value is the area in the left and right tails combined: \(p=0.0055110+0.0055110=0.011022\)
Step 4: Make a decision
The p value (0.011022) is less than the standard 0.05 alpha level, therefore we reject the null hypothesis.
Step 5: State a "real world" conclusion
There is evidence that the proportion of all NFL overtime coin tosses that are won is different from 0.50